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LEARNING / MATHEMATICAL METHODS IN PHYSICS / ALGEBRA OF VECTOR QUANTITIES

Products between vectors

done Figure: interactive
The question

There are three ways to multiply two vectors here. What does each one measure?

Scene 1

One pair, three answers

Take two vectors and multiply them. There is no single answer, because the word multiply is underdetermined. Three different questions are hiding inside it. How much do the vectors overlap? What direction is perpendicular to both? How much space do three of them enclose? Each question has its own product, and each product is exactly one of those answers.

Scene 2

Play with it first

Start with the figure. It puts the three products in one place, one step each. Step through it and watch what each one measures: a projection, a shaded area, a signed volume. The panel prints the live value of whichever product is on screen, so you can see it grow and shrink as you drag.

1-12-23-34-45-51-12-2ABproj of A on BthA . B = |A| |B| cos th = 2.42 x 2.24 x 0.70 = 3.79 (the overlap)|A| = 2.42 |B| = 2.24 th = 45.5°
Step 1 / 3 Drag the vector

The scalar product: overlap

The scalar product answers how much of one vector lies along the other. Decompose AA into a projection along BB and a part across it; only the along part survives, so A⋅B=∣A∣∣B∣cos⁡θA\cdot B = |A||B|\cos\theta. Turn BB and watch the value grow and vanish.
Scene 3

The dot product measures overlap

The dot product keeps only the part of AA that points where BB points. Drop a perpendicular and read the shadow: that is the projection, and its length times the length of BB is A⋅B=∣A∣∣B∣cos⁡θA\cdot B = |A||B|\cos\theta. Two facts fall straight out. At a right angle there is no shadow, so the product is zero however long the vectors are. And when B=AB = A the product becomes ∣A∣2|A|^2, the length, which every frame agrees on. That invariance is why the answer is a single number.

1-12-23-34-45-51-12-2ABproj of A on BthA . B = |A||B| cos th
Scene 4

The cross product measures area

The cross product answers a different question: which direction is perpendicular to both? Two independent vectors span a plane, and exactly one direction is normal to it. The product is that direction, with the area of the parallelogram as its length: ∣A×B∣=∣A∣∣B∣sin⁡θ|A\times B| = |A||B|\sin\theta. It is an area with an arrow on it. Swap the two vectors and the parallelogram is unchanged, but the arrow flips: A×B=−B×AA\times B = -B\times A. And A×A=0A\times A = 0, because a vector encloses no area with itself.

1-12-23-34-45-51-12-2ABA x B comes out of the page|A x B| = |A||B| sin th = the shaded area
Scene 5

The mixed product measures volume

Now take three vectors. B×CB\times C is perpendicular to the base, and dotting it with AA keeps only the height of AA above that base. So A⋅(B×C)A\cdot(B\times C) is base area times height: the volume of the box, with a sign for orientation. Here is the payoff. Drag CC into the plane of AA and BB and the height vanishes, so the volume is zero. A vanishing mixed product is exactly the test for coplanarity. The determinant has been measuring volume all along.

1-12-23-34-45-51-12-23-34-4ABCA . (B x C) = base area x height = signed volumevolume = 2.63 (base area x height)sign: + right-handed
Scene 6

A rule for which to use

A short decision rule for any product you meet. Need how much of one vector lies along another? Take the dot product and get a scalar. Need the direction perpendicular to two? Take the cross product and get a vector. Need the volume three vectors span? Take the mixed product and get a scalar. Units confirm the choice: work must come out as energy, so only a dot product can produce it; angular momentum must come out a vector, so only a cross product can.

needproductyou gethow much lies alongA . Ba scalarwhat is perpendicularA x Ba vectorhow much space is spannedA . (B x C)a scalar
Scene 7

The bigger picture

So the three products are not three conventions. They are three measurements: overlap, area, volume. Everything so far has operated on numbers attached to points. The next question asks how such quantities change from point to point, which is where the study of fields begins.